A 20,000 ohm/volt meter will have an internal resistance of how many ohms on the ten-volt scale?

Earn your NETA ETT Certified Assistant Level 3 with our test prep. Engage with targeted flashcards and multiple choice questions with answers explained. Prepare effectively for your certification exam!

To determine the internal resistance of a 20,000 ohm/volt meter when set at a ten-volt scale, you multiply the volt rating of the scale by the ohm rating of the meter.

The formula to calculate the internal resistance is as follows:

Internal Resistance = Ohm Rating per Volt × Voltage Scale

In this case, since the meter is rated at 20,000 ohms per volt and the scale is set at 10 volts, the calculation would be:

Internal Resistance = 20,000 ohms/volt × 10 volts = 200,000 ohms.

This derived value indicates the resistance that will be presented by the voltmeter when it is measuring a voltage of 10 volts. It’s essential for understanding how much the voltmeter will load the circuit being measured. A higher internal resistance is often advantageous as it minimizes the influence of the voltmeter on the circuit, thus providing a more accurate measurement.

Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy