How do you calculate the capacitance of a 4160V, 60 Hz capacitor bank rated 100kVAR with an Xc of 173.05 ohms?

The calculation of capacitance in this scenario is correctly represented by the formula C = 10^6 / (2 * pi * f * Xc). This formula is derived from the relationship between capacitive reactance (Xc), frequency (f), and capacitance (C).

In this case, Xc is defined as the capacitive reactance measured in ohms, which indicates how much opposition a capacitor presents to alternating current (AC). The formula relates these quantities, where C is capacitance measured in farads, f is the frequency in hertz, and Xc is the capacitive reactance.

To elaborate, the capacitive reactance can be expressed as:

[ Xc = \frac{1}{2 \pi f C} ]

Rearranging this equation to solve for C gives:

[ C = \frac{1}{2 \pi f Xc} ]

Since the formula you mentioned includes a factor of 10^6, this suggests that the capacitance is being calculated in microfarads (μF), where 1 μF = 10^-6 F. The calculations would have to consider not only the values of f and Xc but also this unit conversion factor to arrive