How much is the secondary phase current for a wye-delta transformer with a secondary line voltage of 480 V and a resistive load of 50 ohms in each phase?

To find the secondary phase current for a wye-delta transformer configuration, we first determine the phase voltage from the secondary line voltage. In a wye (Y) configuration, the relationship between line voltage (V_LINE) and phase voltage (V_PHASE) is given by:

V_PHASE = V_LINE / √3

Given a secondary line voltage of 480 V, the phase voltage can be calculated as follows:

V_PHASE = 480 V / √3 ≈ 277 V

Next, we need to calculate the phase current using Ohm's Law, which states:

I_PHASE = V_PHASE / R

Where R is the resistive load per phase, which is given as 50 ohms. Plugging in the values, we find:

I_PHASE = 277 V / 50 ohms ≈ 5.54 A

This calculation leads us to conclude that the secondary phase current is approximately 5.54 Amps.